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Find the products in their exponential form
(a)2^2×4^2×8^2​

Sagot :

Answer:

2 to the power of 12

Step-by-step explanation:

To find the product

2

2

×

4

2

×

8

2

2

2

×4

2

×8

2

 in exponential form, we first express each number with the same base.

Express 4 and 8 as powers of 2:

4

=

2

2

4=2

2

8

=

2

3

8=2

3

Substitute these values back into the expression:

4

2

=

(

2

2

)

2

=

2

2

×

2

=

2

4

4

2

=(2

2

)

2

=2

2×2

=2

4

8

2

=

(

2

3

)

2

=

2

3

×

2

=

2

6

8

2

=(2

3

)

2

=2

3×2

=2

6

So the original expression becomes:

2

2

×

2

4

×

2

6

2

2

×2

4

×2

6

Combine the exponents by using the property of exponents

×

=

+

a

m

×a

n

=a

m+n

:

2

2

×

2

4

×

2

6

=

2

2

+

4

+

6

=

2

12

2

2

×2

4

×2

6

=2

2+4+6

=2

12

Thus, the product in its exponential form is:

2

12

2

12

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