Answered

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The circle below is centered at the point (1, 2) and has a radius of length 3.
What is its equation?
-510
OA. (x-1)²+(y-2)²=
32
OB. (x-2)²+(y-1)² = 32
C. (x-1)²+(y+ 2)² = 9
OD. (x-2)²+(y+ 1)² = 9

Sagot :

Answer:

(x - 1)² + (y - 2)² = 9

Step-by-step explanation:

The equation of a circle in standard form is

• (x - h)² + (y - k)² = r²

(h, k ) are the coordinates of the centre and r is the radius

given centre = (1, 2 ) = (h, k ) and r = 3 , then

(x - 1 )² + (y - 2)² = 3² , that is

(x - 1)² + (y - 2)² = 9

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