Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A car of mass 1000 kg is travelling down a steep hill. The brakes fail and the driver uses a horizontal sand-filled safety road to stop the car.

The car enters the sand at a speed of 10m / s and experiences a constant stopping force of 2500 Ν.

How far does the car travel in the sand before coming to rest?

Sagot :

MathPhys

Answer:

20 m

Explanation:

There are two methods we can use to find the distance traveled. One method is the work-energy theorem, which says the work done by the stopping force is equal to the car's change in kinetic energy. Another method is to use Newton's second law of motion to find the acceleration, then use a kinematic equation to solve for the distance.

Using the work energy theorem, work (W) is equal to the change in kinetic energy (KE). Work is equal to force (F) times distance (d), and kinetic energy is half the mass (m) times the square of the speed (v).

W = ΔKE

Fd = ½ mv²

(2500 N) d = ½ (1000 kg) (10 m/s)²

d = 20 m

Alternatively, using Newton's second law of motion, the net force (F) is equal to the mass (m) times the acceleration (a).

F = ma

-2500 N = (1000 kg) a

a = -2.5 m/s²

Use a kinematic equation, also known as a SUVAT equation.

v² = u² + 2as

(0 m/s)² = (10 m/s)² + 2 (-2.5 m/s²) d

d = 20 m

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.