To find the volume occupied by 4.38 moles of oxygen gas (O2) at Standard Temperature and Pressure (STP), follow these steps:
1. Understand the Concept of STP:
- STP stands for Standard Temperature and Pressure.
- At STP, one mole of any ideal gas occupies a volume of 22.4 liters.
2. Identify the Given Data:
- Number of moles of oxygen gas ([tex]\( \text{O}_2 \)[/tex]) = 4.38 moles.
- Volume occupied by one mole of gas at STP = 22.4 liters.
3. Use the Formula:
- The volume occupied by a given number of moles of gas at STP can be calculated using the formula:
[tex]\[
\text{Volume} = \text{Number of moles} \times \text{Volume per mole at STP}
\][/tex]
4. Perform the Calculation:
- Substitute the values into the formula:
[tex]\[
\text{Volume} = 4.38 \, \text{moles} \times 22.4 \, \text{liters/mole}
\][/tex]
- Calculate the product:
[tex]\[
\text{Volume} = 98.112 \, \text{liters}
\][/tex]
5. Choose the Correct Answer:
- The calculated volume is 98.112 liters.
- Among the given options, the option that matches closest to this calculation is:
[tex]\[
\text{C. 98.1 L}
\][/tex]
Therefore, the volume that 4.38 moles of oxygen gas will occupy at STP is 98.1 liters.
Answer: C. 98.1 L
