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(a) A positive number is 5 times another number. If 24 is added to both the numbers, one
of the new numbers becomes twice the
other new number. Find the numbers.
(b) One of the digits of a 2-digit numb


Sagot :

Alright, let's work through the problem step-by-step.

### Part (a):

1. Setting Up the Variables:
- Let the smaller number be [tex]\( b \)[/tex].
- The larger number is [tex]\( 5 \)[/tex] times the smaller number, so we can represent it as [tex]\( a = 5b \)[/tex].

2. Formulating the Equation with the Condition:
- According to the problem, if we add 24 to both numbers, the larger new number becomes twice the smaller new number. Mathematically, this can be expressed as:
[tex]\[ (a + 24) = 2(b + 24) \][/tex]

3. Substituting for [tex]\( a \)[/tex]:
- We know that [tex]\( a = 5b \)[/tex]. Substituting this into the equation gives:
[tex]\[ (5b + 24) = 2(b + 24) \][/tex]

4. Solving for [tex]\( b \)[/tex]:
- Expand and simplify the equation:
[tex]\[ 5b + 24 = 2b + 48 \][/tex]
- Subtract [tex]\( 2b \)[/tex] from both sides:
[tex]\[ 3b + 24 = 48 \][/tex]
- Subtract 24 from both sides:
[tex]\[ 3b = 24 \][/tex]
- Divide by 3:
[tex]\[ b = 8 \][/tex]

5. Finding [tex]\( a \)[/tex]:
- Substitute [tex]\( b = 8 \)[/tex] back into the equation [tex]\( a = 5b \)[/tex]:
[tex]\[ a = 5 \times 8 = 40 \][/tex]

So, the numbers are:
- The smaller number, [tex]\( b \)[/tex], is [tex]\( 8 \)[/tex].
- The larger number, [tex]\( a \)[/tex], is [tex]\( 40 \)[/tex].

Thus, the two numbers are 8 and 40.

### Part (b):

You mentioned "One of the digits of a 2-digit numb" but did not complete the sentence or provide a clear question. If you can provide the complete question, I'll be happy to help solve it!
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