Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

The current in a coil of 500 turns is changed from zero to 5.43 Amp. There by producing a flux of 8.52 x 10-4 webers. What is the self-inductance of the coil?

Sagot :

Answer:

The magnetic flux through an inductor is the self inductance of coil times the current through it.

Thus

ϕ

=

L

I

=

50

×

10

−

3

H

×

8

×

10

−

3

A

=

4

×

10

−

4

W

b

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.