Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Next O
Heat and Changes in Matter: Mastery Test
4
Submit
Type the correct answer in the box. Express your answer to three significant figures.
A2.30-gram ice cube at water's melting point is dropped into a glass of warm juice and gains enough joules of heat to melt completely. If the heat of
fusion is 334 joules/gram, how much energy was absorbed?
The amount of energy absorbed was
joules.
Reset
Nex


Sagot :

To determine the amount of energy absorbed by a 2.30-gram ice cube melting completely, we use the heat of fusion of ice. The heat of fusion is the amount of energy required to change 1 gram of a substance from solid to liquid at its melting point.

Given:
- Mass of the ice cube ([tex]\( m \)[/tex]) = 2.30 grams
- Heat of fusion of ice ([tex]\( \Delta H_f \)[/tex]) = 334 joules/gram

We use the following formula to calculate the energy ([tex]\( Q \)[/tex]) absorbed:

[tex]\[ Q = m \times \Delta H_f \][/tex]

Substitute the given values into the formula:

[tex]\[ Q = 2.30 \, \text{grams} \times 334 \, \text{joules/gram} \][/tex]

Performing the multiplication:

[tex]\[ Q = 767.9999999999999 \, \text{joules} \][/tex]

Expressing the answer to three significant figures:

[tex]\[ Q \approx 768 \, \text{joules} \][/tex]

Thus, the amount of energy absorbed was [tex]\( 768 \)[/tex] joules.