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The vertices of a triangle are located at (0, 1), (3, 1), and (0, 2). To the nearest hundredth, what is the perimeter of the triangle?
A 6.16 units
B 6.76 units
9.77 units
10.83 units


Sagot :

Answer:

Your options are wrong

The answer is 7.16 units

as you can find the length using the distance formula

d^2 = (x2 - x1)^2 + (y2 - y1 )^2

which would give one side as 3 units the other as 1 and the third one as sqroot 10

which would add up too 7.16 units