Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To determine the amount of sodium chloride needed to make 19 liters of a solution with a concentration of 3.2 grams per liter, we need to use the formula for calculating the total mass of solute in the solution. The formula is:
[tex]\[ \text{Mass of solute} = \text{Volume of solution} \times \text{Concentration of solute} \][/tex]
Given the following values:
- The volume of the solution = 19 liters
- The concentration of sodium chloride = 3.2 grams per liter
We plug these values into the formula:
[tex]\[ \text{Mass of sodium chloride} = 19 \, \text{L} \times 3.2 \, \text{g/L} \][/tex]
By multiplying these together:
[tex]\[ \text{Mass of sodium chloride} = 60.8 \, \text{g} \][/tex]
Hence, to make 19 liters of the solution with a concentration of 3.2 grams of sodium chloride per liter, you need 60.8 grams of sodium chloride.
[tex]\[ \text{Mass of solute} = \text{Volume of solution} \times \text{Concentration of solute} \][/tex]
Given the following values:
- The volume of the solution = 19 liters
- The concentration of sodium chloride = 3.2 grams per liter
We plug these values into the formula:
[tex]\[ \text{Mass of sodium chloride} = 19 \, \text{L} \times 3.2 \, \text{g/L} \][/tex]
By multiplying these together:
[tex]\[ \text{Mass of sodium chloride} = 60.8 \, \text{g} \][/tex]
Hence, to make 19 liters of the solution with a concentration of 3.2 grams of sodium chloride per liter, you need 60.8 grams of sodium chloride.
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.