Sure, let's solve this step-by-step.
1. Understand the problem:
- We are given a cylindrical pipe with a diameter of 5 feet and a length (height) of 27 feet.
- We need to find the volume of this cylinder.
- Use the value [tex]\( \pi = 3.14 \)[/tex].
- Round the final answer to the nearest whole number.
2. Recall the formula for the volume of a cylinder:
[tex]\[
V = \pi r^2 h
\][/tex]
Where:
- [tex]\( V \)[/tex] is the volume
- [tex]\( r \)[/tex] is the radius of the cylinder
- [tex]\( h \)[/tex] is the height (or length) of the cylinder
- [tex]\( \pi \)[/tex] is a mathematical constant (approximately 3.14 for our calculations)
3. Calculate the radius of the cylinder:
- The diameter of the cylinder is 5 feet.
- The radius ([tex]\( r \)[/tex]) is half of the diameter:
[tex]\[
r = \frac{\text{diameter}}{2} = \frac{5 \text{ ft}}{2} = 2.5 \text{ ft}
\][/tex]
4. Use the formula to find the volume:
Substitute [tex]\( r = 2.5 \)[/tex] feet, [tex]\( h = 27 \)[/tex] feet, and [tex]\( \pi = 3.14 \)[/tex] into the volume formula:
[tex]\[
V = 3.14 \times (2.5)^2 \times 27
\][/tex]
5. Calculate the square of the radius:
[tex]\[
(2.5)^2 = 6.25
\][/tex]
6. Substitute and calculate:
[tex]\[
V = 3.14 \times 6.25 \times 27
\][/tex]
7. Multiply the values:
[tex]\[
V = 3.14 \times 6.25 = 19.625
\][/tex]
[tex]\[
V = 19.625 \times 27 = 529.875
\][/tex]
8. Round the final answer to the nearest whole number:
[tex]\[
V \approx 530
\][/tex]
So, the volume of the cylindrical construction pipe is approximately [tex]\( 530 \)[/tex] cubic feet.
