Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To graph the equation [tex]\( p(x) = -x^3 \)[/tex] by plotting points, follow these steps:
### Step-by-Step Solution
1. Choose a set of x-values:
Select a range of x-values that gives you a broad view of the behavior of the function. Let's choose integers from [tex]\( -3 \)[/tex] to [tex]\( 3 \)[/tex].
2. Calculate corresponding y-values:
For each x-value, compute the corresponding y-value using the function [tex]\( p(x) = -x^3 \)[/tex].
3. Plot the points:
Plot each (x, y) pair on a coordinate plane.
4. Draw the curve:
After plotting the points, connect them smoothly to show the overall shape of the function.
### Choosing x-values and calculating y-values
Let's choose the x-values [tex]\( -3, -2, -1, 0, 1, 2, 3 \)[/tex]:
[tex]\[ \begin{align*} p(-3) &= -(-3)^3 = -(-27) = 27 \\ p(-2) &= -(-2)^3 = -(-8) = 8 \\ p(-1) &= -(-1)^3 = -(-1) = 1 \\ p(0) &= -(0)^3 = 0 \\ p(1) &= -(1)^3 = -1 \\ p(2) &= -(2)^3 = -8 \\ p(3) &= -(3)^3 = -27 \\ \end{align*} \][/tex]
So, the (x, y) pairs are:
[tex]\[ \begin{align*} (-3, 27) \\ (-2, 8) \\ (-1, 1) \\ (0, 0) \\ (1, -1) \\ (2, -8) \\ (3, -27) \\ \end{align*} \][/tex]
### Plotting the Points
1. Create a coordinate plane with the x and y axes.
2. Plot each of the points (x, y) determined above.
### Drawing the Curve
Connect the plotted points with a smooth curve, as this is a continuous function. The function [tex]\( p(x) = -x^3 \)[/tex] is cubic and has the following characteristics:
- It passes through the origin (0, 0).
- For [tex]\( x > 0 \)[/tex], [tex]\( p(x) \)[/tex] is decreasing because [tex]\( -x^3 \)[/tex] is negative and becomes more negative as [tex]\( x \)[/tex] increases.
- For [tex]\( x < 0 \)[/tex], [tex]\( p(x) \)[/tex] is increasing because [tex]\( -x^3 \)[/tex] turns negative [tex]\( x \)[/tex] values into positive.
### Graph Description
- The graph will be symmetrical with respect to the origin (it is an odd function).
- As [tex]\( x \)[/tex] approaches positive infinity, [tex]\( p(x) \)[/tex] will approach negative infinity.
- As [tex]\( x \)[/tex] approaches negative infinity, [tex]\( p(x) \)[/tex] will approach positive infinity.
This is the shape and key properties of the graph of [tex]\( p(x) = -x^3 \)[/tex].
### Step-by-Step Solution
1. Choose a set of x-values:
Select a range of x-values that gives you a broad view of the behavior of the function. Let's choose integers from [tex]\( -3 \)[/tex] to [tex]\( 3 \)[/tex].
2. Calculate corresponding y-values:
For each x-value, compute the corresponding y-value using the function [tex]\( p(x) = -x^3 \)[/tex].
3. Plot the points:
Plot each (x, y) pair on a coordinate plane.
4. Draw the curve:
After plotting the points, connect them smoothly to show the overall shape of the function.
### Choosing x-values and calculating y-values
Let's choose the x-values [tex]\( -3, -2, -1, 0, 1, 2, 3 \)[/tex]:
[tex]\[ \begin{align*} p(-3) &= -(-3)^3 = -(-27) = 27 \\ p(-2) &= -(-2)^3 = -(-8) = 8 \\ p(-1) &= -(-1)^3 = -(-1) = 1 \\ p(0) &= -(0)^3 = 0 \\ p(1) &= -(1)^3 = -1 \\ p(2) &= -(2)^3 = -8 \\ p(3) &= -(3)^3 = -27 \\ \end{align*} \][/tex]
So, the (x, y) pairs are:
[tex]\[ \begin{align*} (-3, 27) \\ (-2, 8) \\ (-1, 1) \\ (0, 0) \\ (1, -1) \\ (2, -8) \\ (3, -27) \\ \end{align*} \][/tex]
### Plotting the Points
1. Create a coordinate plane with the x and y axes.
2. Plot each of the points (x, y) determined above.
### Drawing the Curve
Connect the plotted points with a smooth curve, as this is a continuous function. The function [tex]\( p(x) = -x^3 \)[/tex] is cubic and has the following characteristics:
- It passes through the origin (0, 0).
- For [tex]\( x > 0 \)[/tex], [tex]\( p(x) \)[/tex] is decreasing because [tex]\( -x^3 \)[/tex] is negative and becomes more negative as [tex]\( x \)[/tex] increases.
- For [tex]\( x < 0 \)[/tex], [tex]\( p(x) \)[/tex] is increasing because [tex]\( -x^3 \)[/tex] turns negative [tex]\( x \)[/tex] values into positive.
### Graph Description
- The graph will be symmetrical with respect to the origin (it is an odd function).
- As [tex]\( x \)[/tex] approaches positive infinity, [tex]\( p(x) \)[/tex] will approach negative infinity.
- As [tex]\( x \)[/tex] approaches negative infinity, [tex]\( p(x) \)[/tex] will approach positive infinity.
This is the shape and key properties of the graph of [tex]\( p(x) = -x^3 \)[/tex].
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.