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a 314 kg crate is pulled by two horizontal forces. the first force is 255 n at a 43.5 angle and the second is 360 n at a 212 angle. what is the acceleration of the crate?

Sagot :

Answer:

0.386 m/s² at 187°

Explanation:

According to Newton's second law of motion, the net force (ΣF) on an object is equal to its mass (m) times its acceleration (a). By resolving the forces into x and y components, we can find the components of the acceleration vector. From there, we can use Pythagorean theorem to find the magnitude of the acceleration, and trigonometry to find the direction.

The x component of each force is F cos θ, where F is the magnitude of the force and θ is the direction. The net force in the x direction is therefore:

ΣFₓ = 255 N cos 43.5° + 360 N cos 212°

ΣFₓ = -120.3 N

The y component of each force is F sin θ, where F is the magnitude of the force and θ is the direction. The net force in the y direction is therefore:

ΣFᵧ = 255 N sin 43.5° + 360 N sin 212°

ΣFᵧ = -15.24 N

Using Newton's second law of motion, the components of the acceleration are:

ΣF = ma

a = ΣF / m

aₓ = -120.3 N / 314 kg = -0.383 m/s²

aᵧ = -15.24 N / 314 kg = -0.049 m/s²

Using Pythagorean theorem, the magnitude of the acceleration is:

a² = aₓ² + aᵧ²

a² = (-0.383 m/s²)² + (-0.049 m/s²)²

a = 0.386 m/s²

Using trigonometry, the direction of the acceleration is:

tan θ = aᵧ / aₓ

tan θ = -0.049 m/s² / -0.383 m/s²

θ = 187°