Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A student lifts a 30 kg bag of dog food to a height of 3.0 m above the floor in 5.0 s. Calculate the power output of the student (in watt).

Sagot :

kirigayuuki02
To calculate the power output of the student, we can use the formula:

Power = Work / Time

First, let's calculate the work done by the student:

Work = Force × Distance

The force exerted by the student can be calculated using the formula:

Force = Mass × Gravity

where the mass is 30 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Force = 30 kg × 9.8 m/s^2

Next, we can calculate the distance by multiplying the height (3.0 m) by the gravitational acceleration.

Distance = 3.0 m

Now, we can calculate the work:

Work = Force × Distance

Finally, we can calculate the power output by dividing the work by the time (5.0 s):

Power = Work / Time

Let's calculate the power:

Force = 30 kg × 9.8 m/s^2 = 294 N
Distance = 3.0 m
Work = Force × Distance = 294 N × 3.0 m = 882 J
Time = 5.0 s
Power = Work / Time = 882 J / 5.0 s = 176 W

Therefore, the power output of the student is 176 watts.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.