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What is the power of a
motor which transfers
10kJ of energy in 25s?


Sagot :

To determine the power of a motor, we need to use the formula for power, which is given by:

[tex]\[ P = \frac{E}{t} \][/tex]

Here:
- [tex]\( P \)[/tex] is the power.
- [tex]\( E \)[/tex] is the energy transferred.
- [tex]\( t \)[/tex] is the time taken.

1. Identify the given values:
- Energy transferred: [tex]\( E = 10 \, \text{kJ} \)[/tex]
- Time taken: [tex]\( t = 25 \, \text{s} \)[/tex]

2. Convert the energy into the standard unit of Joules (J):
- [tex]\( 1 \, \text{kJ} = 1000 \, \text{J} \)[/tex]
Therefore,
[tex]\[ E = 10 \, \text{kJ} \times 1000 \, \text{J/kJ} = 10000 \, \text{J} \][/tex]

3. Substitute the values into the formula:
[tex]\[ P = \frac{E}{t} = \frac{10000 \, \text{J}}{25 \, \text{s}} \][/tex]

4. Calculate the power:
[tex]\[ P = \frac{10000 \, \text{J}}{25 \, \text{s}} = 400 \, \text{W} \][/tex]

Therefore, the power of the motor is [tex]\( 400 \, \text{W} \)[/tex].