Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

a water balloon is tossed forward at 4.2 m/s with an angle of 55 degrees above the horizontal how much time will have passed before the water ballon reaches its highest point

Sagot :

Answer:

0.35 s

Explanation:

The water balloon is a projectile in free fall, meaning that the only force on the balloon is gravity. Since the balloon has a constant acceleration, we can use kinematic equations, also known as SUVAT equations, to model the motion. In this case, we will use:

v = u + at

where

  • v is the final velocity (final speed)
  • u is the initial velocity (initial speed)
  • a is the acceleration
  • t is the time

In the vertical direction, the final speed of the balloon is v = 0 m/s, and the initial speed is u = 4.2 m/s sin 55°. The acceleration is gravity, a = -9.8 m/s². Plugging in values and solving for time:

v = u + at

0 m/s = 4.2 m/s sin 55° + (-9.8 m/s²) t

t = 0.35 s