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a water balloon is tossed forward at 4.2 m/s with an angle of 55 degrees above the horizontal how much time will have passed before the water ballon reaches its highest point

Sagot :

MathPhys

Answer:

0.35 s

Explanation:

The water balloon is a projectile in free fall, meaning that the only force on the balloon is gravity. Since the balloon has a constant acceleration, we can use kinematic equations, also known as SUVAT equations, to model the motion. In this case, we will use:

v = u + at

where

  • v is the final velocity (final speed)
  • u is the initial velocity (initial speed)
  • a is the acceleration
  • t is the time

In the vertical direction, the final speed of the balloon is v = 0 m/s, and the initial speed is u = 4.2 m/s sin 55°. The acceleration is gravity, a = -9.8 m/s². Plugging in values and solving for time:

v = u + at

0 m/s = 4.2 m/s sin 55° + (-9.8 m/s²) t

t = 0.35 s

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