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what is the inverse of f(x)= 1/3x + 2

Sagot :

Answer:

[tex]f^{-1} (x) =[/tex] 3x - 6

Step-by-step explanation:

f(x)= 1/3x + 2

y= 1/3x + 2

re arrange to make it in terms of y

3y = x + 6 (I multiplied across by 3)

-x = 6 - 3y

x = 3y - 6

change the x's to y's and vice versa

y = 3x - 6

notation

[tex]f^{-1} (x) =[/tex] 3x - 6

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