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S
raph
2)
A parabola can be drawn given a focus of (10, -6) and a directrix of x = 6. Write the equation of the
parabola in any form.
Key
evel 1)
evel 1)
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y
12
11
10
219
9
9
54321
directrix
x
1 2 3 4 5 6 7 8 9 10 11 12
-2
-12-11-10 -9 -8 -7 -6 -5 -4 -3 -2 -1
-3
-4
-5
-6
-7
-8
-9
-10
-11
-12
-TNSTCOTON
Answer Attempt 1 out of 2
MacBook Air
F (10, -6)
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Sagot :

To find the equation of a parabola given a focus and a directrix, follow these steps:

1. Identify the Focus and Directrix:
- Focus: [tex]\( (10, -6) \)[/tex]
- Directrix: [tex]\( x = 6 \)[/tex]

2. Determine the Vertex:
The vertex of a parabola lies midway between the focus and the directrix. If the directrix is a vertical line [tex]\( x = 6 \)[/tex], then it is vertical by symmetry about an axis parallel to the y-axis.

The x-coordinate of the vertex is the midpoint between the x-coordinate of the focus and the directrix:
[tex]\[ h = \frac{10 + 6}{2} = 8.0 \][/tex]

The y-coordinate of the vertex remains the same as the y-coordinate of the focus since the directrix is a vertical line:
[tex]\[ k = -6 \][/tex]

3. Calculate the Distance [tex]\( p \)[/tex] (distance from the vertex to the focus):
[tex]\[ p = 10 - h = 10 - 8 = 2.0 \][/tex]

4. Write the Equation of the Parabola:
The standard form of the equation of a parabola with a vertical axis and vertex at [tex]\( (h, k) \)[/tex] is:
[tex]\[ (x - h)^2 = 4p(y - k) \][/tex]

Substituting [tex]\( h = 8.0 \)[/tex], [tex]\( k = -6 \)[/tex], and [tex]\( p = 2 \)[/tex]:
[tex]\[ (x - 8.0)^2 = 4 \times 2.0 (y - (-6)) \][/tex]
Simplifying this:
[tex]\[ (x - 8.0)^2 = 8.0(y + 6) \][/tex]

Hence, the equation of the parabola is:
[tex]\[ (x - 8.0)^2 = 8.0(y + 6) \][/tex]

Summing up:
- Vertex: [tex]\( (8.0, -6) \)[/tex]
- Distance [tex]\( p \)[/tex]: [tex]\( 2.0 \)[/tex]
- Equation of the parabola: [tex]\( (x - 8.0)^2 = 8.0(y + 6) \)[/tex]