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Sagot :
Answer:not equal
Step-by-step explanation:Given the expression \(\frac{a}{b} + \frac{x}{x}\), we need to determine if it will be less than, equal to, or greater than \(\frac{3}{4}\) under the condition \(\frac{a}{b} = \frac{3}{4}\).
First, let's rewrite the expression:
\[
\frac{a}{b} + \frac{x}{x}
\]
Notice that \(\frac{x}{x}\) simplifies to 1, as any non-zero number divided by itself is 1. So, we can simplify the given expression to:
\[
\frac{a}{b} + 1
\]
We know from the problem statement that:
\[
\frac{a}{b} = \frac{3}{4}
\]
Substituting this value into the expression, we get:
\[
\frac{3}{4} + 1
\]
Next, let's add these fractions. To add the fraction \(\frac{3}{4}\) and 1, we convert 1 to a fraction with a denominator of 4:
\[
1 = \frac{4}{4}
\]
Now, we can add the fractions:
\[
\frac{3}{4} + \frac{4}{4} = \frac{3+4}{4} = \frac{7}{4}
\]
Thus, the value of the expression \(\frac{a}{b} + \frac{x}{x}\) is \(\frac{7}{4}\).
To determine how \(\frac{7}{4}\) compares to \(\frac{3}{4}\), we can observe that:
\[
\frac{7}{4} > \frac{3}{4}
\]
Therefore, the value of \(\frac{a}{b} + \frac{x}{x}\) is greater than \(\frac{3}{4}\).
In conclusion, \(\frac{a}{b} + \frac{x}{x}\) will be greater than \(\frac{3}{4}\) given that \(\frac{a}{b} = \frac{3}{4}\).
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