Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Determine the number of moles of sodium hydroxide (NaOH) needed to neutralize 25 mL of 0.1 M hydrochloric acid (HCl).

Sagot :

26uffikn

To determine the number of moles of sodium hydroxide (NaOH) needed to neutralize 25 mL of 0.1 M hydrochloric acid (HCl), follow these steps:

1. Calculate the moles of HCl.

  - Molarity of HCl = 0.1 M

  - Volume of HCl = 25 mL = 0.025 L

  Moles of HCl = Molarity * Volume

  Moles of HCl = 0.1 * 0.025

  Moles of HCl = 0.0025 moles

2. Since the reaction between NaOH and HCl is 1:1, the moles of NaOH needed will be equal to the moles of HCl.

  Moles of NaOH needed = 0.0025 moles

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.