Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Challenge Problems1. A man has a daughter and a son. The son is three years older than the daughter. In one year, the man will be six times as old as the daughter is now. In ten years, the man would be fourteen years older than the combined ages of his children at that time. What is the present age of-the man.

Sagot :

Step-by-step explanation:

Let the man's current age be given as M

Let his son's age be given as A

Let his daughter's age be given as D

From the question

S= 3+D.........(1)

In one year,

M+1 = 6D.....(2)

In sixteen years,

M+16 = (S+16) + (D+16).......(3)

From (1) to (3)

M+16 = (3+D+16) + (D+16)

M+16 = 2D + 35

M = 2D + 19........(4)

From (4) to (2)

(2D + 19) + 1 = 6D

2D + 20 = 6D

.....

Complete later

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.