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in geometric progression if the first term is 4 and the common ratio is 2 what is the third term

Sagot :

Answer:

third term a₃ = 16

Step-by-step explanation:

In a geometric progression

Each term is the preceding term, multiplied by the common ratio.

given

a₁ = 4 , then

a₂ = a₁ × 4 = 8

a₃ = a₂ × 4 = 16

The third term a₃ = 16