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What is the value of the heat transferred when 0.898 moles of manganese, Mn, is burned to form Mn₃O₄(s) at standard state conditions? (Hint: Begin by writing the balanced, chemical equation) Mn(s) +2/3o₂(g) to 1/3Mn₃o₄(s) and given ΔHբ for Mn(s) = 0 kJ/mol and ΔHf for Mn₃O₄(s) = -1378.83 kJ/mol . Can you answer the following question?

Sagot :

Answer:

462.66 kj/mol

Explanation:

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