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Log2(3x-10)=log2(14-x)

Sagot :

Answer:

X = 6

Step-by-step explanation:

To solve the equation log2(3x10) = log2(14-x), we can use the property of logarithms that states if loga (x) = loga (y), then x = y.

1. Set the expressions inside the logarithms equal to each other:

3x1014-x

2. Simplify the equation by solving for x:

3x+x=14+10

4x = 24

X = 6

Therefore, the solution to the equation is x = 6.

Answer:

x = 6

Step-by-step explanation:

Using the property of logarithms

• [tex]log_{b}[/tex] x = [tex]log_{b}[/tex] y ⇒ x = y

given

[tex]log_{2}[/tex] (3x - 10) = [tex]log_{2}[/tex] (14 - x) , then

3x - 10 = 14 - x ( add x to both sides )

4x - 10 = 14 ( add 10 to both sides )

4x = 24 ( divide both sides by 4 )

x = 6