Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The sum of a geometric series is 31.5. The first term of the series is 16, and its common ratio is 0.5. How many terms are there in the series?
(Type a whole number.)

Sagot :

Sure! To find the number of terms in a geometric series, we need to use the formula for the sum of a geometric series:

[tex]\[ S_n = a \frac{1 - r^n}{1 - r} \][/tex]

where:
- [tex]\( S_n \)[/tex] is the sum of the series,
- [tex]\( a \)[/tex] is the first term,
- [tex]\( r \)[/tex] is the common ratio,
- [tex]\( n \)[/tex] is the number of terms.

Given:
- The sum of the series [tex]\( S_n = 31.5 \)[/tex],
- The first term [tex]\( a = 16 \)[/tex],
- The common ratio [tex]\( r = 0.5 \)[/tex].

To find the number of terms [tex]\( n \)[/tex], we rearrange the formula to solve for [tex]\( n \)[/tex]:

1. Multiply both sides of the equation by [tex]\( 1 - r \)[/tex]:

[tex]\[ S_n (1 - r) = a (1 - r^n) \][/tex]

2. Substitute the given values:

[tex]\[ 31.5 (1 - 0.5) = 16 (1 - 0.5^n) \][/tex]

3. Calculate [tex]\( 1 - 0.5 \)[/tex]:

[tex]\[ 31.5 \times 0.5 = 16 \times (1 - 0.5^n) \][/tex]

[tex]\[ 15.75 = 16 \times (1 - 0.5^n) \][/tex]

4. Divide both sides by 16:

[tex]\[ \frac{15.75}{16} = 1 - 0.5^n \][/tex]

[tex]\[ 0.984375 = 1 - 0.5^n \][/tex]

5. Subtract 1 from both sides and multiply by -1:

[tex]\[ 0.5^n = 1 - 0.984375 \][/tex]

[tex]\[ 0.5^n = 0.015625 \][/tex]

6. Now, take the logarithm of both sides (base 10 or natural logarithm):

[tex]\[ \log(0.5^n) = \log(0.015625) \][/tex]

[tex]\[ n \log(0.5) = \log(0.015625) \][/tex]

7. Solve for [tex]\( n \)[/tex] by dividing both sides by [tex]\( \log(0.5) \)[/tex]:

[tex]\[ n = \frac{\log(0.015625)}{\log(0.5)} \][/tex]

8. Calculate the logarithms and solve for [tex]\( n \)[/tex]:

[tex]\[ n = \frac{\log(0.015625)}{\log(0.5)} = 6 \][/tex]

So, there are 6 terms in the series.