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Twice the difference of a number and 8 is equal
to three times the sum of the number and 3.
Find the number.


Sagot :

Certainly! Let's solve the given problem step-by-step.

The problem states:
"Twice the difference of a number and 8 is equal to three times the sum of the number and 3."

1. Define the variable:
Let [tex]\( x \)[/tex] be the number we need to find.

2. Set up the equation:
Twice the difference of a number and 8 can be written as:
[tex]\[ 2(x - 8) \][/tex]
Three times the sum of the number and 3 can be written as:
[tex]\[ 3(x + 3) \][/tex]

3. Form the equation:
According to the problem, these two expressions are equal. Therefore, we have:
[tex]\[ 2(x - 8) = 3(x + 3) \][/tex]

4. Simplify the equation:
Distribute the constants on both sides:
[tex]\[ 2x - 16 = 3x + 9 \][/tex]

5. Isolate the variable:
Get all terms involving [tex]\( x \)[/tex] on one side of the equation and constants on the other side. We can start by subtracting [tex]\( 2x \)[/tex] from both sides:
[tex]\[ -16 = x + 9 \][/tex]

6. Solve for [tex]\( x \)[/tex]:
Subtract 9 from both sides to isolate [tex]\( x \)[/tex]:
[tex]\[ -25 = x \][/tex]

So, the number is:
[tex]\[ x = -25 \][/tex]
Thus, the solution to the problem is [tex]\( -25 \)[/tex].
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