To solve the equation [tex]\(5ax + 3ax = 4ax + 12\)[/tex] for [tex]\(x\)[/tex]:
1. Combine like terms on both sides:
[tex]\[
5ax + 3ax = 8ax
\][/tex]
So, the equation becomes:
[tex]\[
8ax = 4ax + 12
\][/tex]
2. Move all terms involving [tex]\(x\)[/tex] to one side:
Subtract [tex]\(4ax\)[/tex] from both sides:
[tex]\[
8ax - 4ax = 12
\][/tex]
Simplifying the left-hand side, we get:
[tex]\[
4ax = 12
\][/tex]
3. Solve for [tex]\(x\)[/tex]:
Divide both sides of the equation by [tex]\(4a\)[/tex]:
[tex]\[
x = \frac{12}{4a}
\][/tex]
Simplifying the fraction, we find:
[tex]\[
x = \frac{3}{a}
\][/tex]
Therefore, the solution is [tex]\( x = \frac{3}{a} \)[/tex], which corresponds to option B.
So, the correct answer is:
[tex]\[
\boxed{\frac{3}{a}}
\][/tex]
