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Add or subtract. If not possible, choose undefined.

[tex]\[
\left[\begin{array}{llll}
5 & 2 & -1 & 3
\end{array}\right] + \left[\begin{array}{llll}
1 & -6 & -6 & -3
\end{array}\right]
\][/tex]

A. [tex]\(\left[\begin{array}{llll}
6 & -4 & 5 & 6
\end{array}\right]\)[/tex]

B. [tex]\(\left[\begin{array}{llll}
4 & 8 & 5 & 6
\end{array}\right]\)[/tex]

C. [tex]\(\left[\begin{array}{llll}
6 & -4 & -7 & 0
\end{array}\right]\)[/tex]

D. Undefined


Sagot :

To determine if we can add or subtract the given vectors, we need to ensure that both vectors have the same dimensions. Given two vectors [tex]\( \mathbf{a} \)[/tex] and [tex]\( \mathbf{b} \)[/tex], vector addition [tex]\( \mathbf{a} + \mathbf{b} \)[/tex] or subtraction [tex]\( \mathbf{a} - \mathbf{b} \)[/tex] can only be performed if:

1. Both vectors have the same number of components, meaning the same length.

Let's look at each part of this problem.

The first part of the expression is:
[tex]\[ \left[ \begin{array}{llll} 5 & 2 & -1 & 3 \end{array} \right] + \left[ \begin{array}{llll} 1 & -6 & -6 & -3 \end{array} \right] \][/tex]
Both vectors have the same number of components (4 each). So, we can add them component-wise:
[tex]\[ \left[5 + 1, 2 + (-6), -1 + (-6), 3 + (-3)\right] = \left[6, -4, -7, 0\right] \][/tex]

This results in a new vector:
[tex]\[ \left[ \begin{array}{llll} 6 & -4 & -7 & 0 \end{array} \right] \][/tex]

Now, the problem asks to compare this result to the given vectors:
[tex]\[ \begin{array}{llll} \left[ \begin{array}{llll} 6 & -4 & 5 & 6 \end{array} \right] \\ \left[ \begin{array}{llll} 4 & 8 & 5 & 6 \end{array} \right] \\ \left[ \begin{array}{llll} 6 & -4 & -7 & 0 \end{array} \right] \end{array} \][/tex]

The calculated vector [tex]\(\left[6, -4, -7, 0\right]\)[/tex] is:

- Not equal to [tex]\(\left[6, -4, 5, 6\right]\)[/tex]
- Not equal to [tex]\(\left[4, 8, 5, 6\right]\)[/tex]
- But is equal to [tex]\(\left[6, -4, -7, 0\right]\)[/tex]

Thus, the last given vector matches our resulting vector.

In summary:

- The vectors [tex]\(\left[5, 2, -1, 3\right]\)[/tex] and [tex]\(\left[1, -6, -6, -3\right]\)[/tex] can indeed be added.
- The correct resultant vector is [tex]\(\left[6, -4, -7, 0\right]\)[/tex].