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Sagot :
To determine which values affect the net force on the skier, we need to consider the forces involved and how they interact.
1. Skier's Weight: This is the gravitational force acting on the skier, pulling them down the slope. Given as [tex]\(608 \, \text{N}\)[/tex] in the forward direction.
2. Force of Friction: This is the resistance force between the skis and the snow, acting backwards. Given as [tex]\(6 \, \text{N}\)[/tex] in the backward direction.
3. Force of Air Resistance: This is the air pushing against the skier as they move forward, also a form of resistance. Given as [tex]\(0.5 \, \text{N}\)[/tex] in the backward direction.
4. Velocity: This represents the speed and direction of the skier’s motion. While important for understanding the skier's movement, it does not itself directly affect the net force acting on the skier.
To find the net force, we sum all the forces acting on the skier, taking into account their directions. Since the skier's weight is acting forward and both the force of friction and the air resistance are acting backward, we subtract the backward forces from the forward force to calculate the net force.
The net force [tex]\( F_\text{net} \)[/tex] is given by:
[tex]\[ F_\text{net} = \text{Weight} - (\text{Force of friction} + \text{Force of air resistance}) \][/tex]
Plugging in the values:
[tex]\[ F_\text{net} = 608 \, \text{N} - (6 \, \text{N} + 0.5 \, \text{N}) \][/tex]
[tex]\[ F_\text{net} = 608 \, \text{N} - 6.5 \, \text{N} \][/tex]
[tex]\[ F_\text{net} = 601.5 \, \text{N} \][/tex]
Therefore, the values that affect the net force on the skier are the skier's weight, the force of friction between the skis and snow, and the force of air resistance. The velocity does not directly affect the net force calculation but provides context for the skier's motion.
Given the details above, the correct answer is:
B. The skier's weight, the force of friction between the skis and snow, and the force of air resistance.
1. Skier's Weight: This is the gravitational force acting on the skier, pulling them down the slope. Given as [tex]\(608 \, \text{N}\)[/tex] in the forward direction.
2. Force of Friction: This is the resistance force between the skis and the snow, acting backwards. Given as [tex]\(6 \, \text{N}\)[/tex] in the backward direction.
3. Force of Air Resistance: This is the air pushing against the skier as they move forward, also a form of resistance. Given as [tex]\(0.5 \, \text{N}\)[/tex] in the backward direction.
4. Velocity: This represents the speed and direction of the skier’s motion. While important for understanding the skier's movement, it does not itself directly affect the net force acting on the skier.
To find the net force, we sum all the forces acting on the skier, taking into account their directions. Since the skier's weight is acting forward and both the force of friction and the air resistance are acting backward, we subtract the backward forces from the forward force to calculate the net force.
The net force [tex]\( F_\text{net} \)[/tex] is given by:
[tex]\[ F_\text{net} = \text{Weight} - (\text{Force of friction} + \text{Force of air resistance}) \][/tex]
Plugging in the values:
[tex]\[ F_\text{net} = 608 \, \text{N} - (6 \, \text{N} + 0.5 \, \text{N}) \][/tex]
[tex]\[ F_\text{net} = 608 \, \text{N} - 6.5 \, \text{N} \][/tex]
[tex]\[ F_\text{net} = 601.5 \, \text{N} \][/tex]
Therefore, the values that affect the net force on the skier are the skier's weight, the force of friction between the skis and snow, and the force of air resistance. The velocity does not directly affect the net force calculation but provides context for the skier's motion.
Given the details above, the correct answer is:
B. The skier's weight, the force of friction between the skis and snow, and the force of air resistance.
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