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Workings of a potential energy of a man who pushes a drum of oil 9kg up an inclined plane 5 metres high s

Sagot :

jacob193

Answer:

The gravitational potential energy of the drum would have increased by [tex]450\; {\rm J}[/tex], assuming that [tex]g = 10\; {\rm N\cdot kg^{-1}}[/tex].

Step-by-step explanation:

When an object of mass [tex]m[/tex] in a gravitational field of constant strength [tex]g[/tex] moves by a distance of [tex]\Delta h[/tex] in the direction of the field lines, the gravitational potential energy ([tex]\text{GPE}[/tex]) gained would be:

[tex]\displaystyle \text{GPE} = m\, g\, \Delta h[/tex].

In this question, it is given that:

  • [tex]m = 9\; {\rm kg}[/tex] is the mass of the object that was moved.
  • [tex]\Delta h = 5\; {\rm m}[/tex] is the displacement of the object in the direction of the gravitational field lines (upwards.)

Assuming that [tex]g = 10\; {\rm N\cdot kg^{-1}}[/tex], the gravitational potential energy that was gained would be:

[tex]\begin{aligned}(\text{GPE}) &= m\, g\, \Delta h \\ &= (9\; {\rm kg})\, (10\; {\rm N \cdot kg^{-1}})\, (5\; {\rm m}) \\ &= 450\; {\rm J}\end{aligned}[/tex].

(Note that [tex]1\; {\rm N\cdot m^{-1}} = 1\; {\rm J}[/tex].)

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