To find out how much power is dissipated by an electric oven when 30 A of current flows through a resistance of 10 ohms, we can use the formula for electrical power dissipation in resistors. The formula is:
[tex]\[ P = I^2 \times R \][/tex]
where:
- [tex]\( P \)[/tex] is the power dissipated,
- [tex]\( I \)[/tex] is the current flowing through the resistance,
- [tex]\( R \)[/tex] is the resistance.
Given:
- [tex]\( I = 30 \)[/tex] A (current),
- [tex]\( R = 10 \)[/tex] ohms (resistance).
Using the formula:
[tex]\[ P = (30 \, \text{A})^2 \times 10 \, \Omega \][/tex]
This evaluates to:
[tex]\[ P = 900 \times 10 \][/tex]
So, the power dissipated is:
[tex]\[ P = 9000 \, \text{W} \][/tex]
Since 1 kW (kilowatt) is equal to 1000 W (watts), we convert 9000 W to kW:
[tex]\[ P = 9000 \, \text{W} \div 1000 = 9 \, \text{kW} \][/tex]
Hence, the correct answer is:
O a. 9 kW
