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If [tex]\( p \Rightarrow q \)[/tex] and [tex]\( q \Rightarrow r \)[/tex], which statement must be true?

A. [tex]\( s \Rightarrow p \)[/tex]
B. [tex]\( r \Rightarrow p \)[/tex]
C. [tex]\( p \Rightarrow s \)[/tex]
D. [tex]\( p \Rightarrow r \)[/tex]

Sagot :

To determine which statement must be true given [tex]$p \Rightarrow q$[/tex] and [tex]$q \Rightarrow r$[/tex], let's analyze the logical implications.

1. Understanding Implications:
- The implication [tex]$p \Rightarrow q$[/tex] means that if [tex]$p$[/tex] is true, then [tex]$q$[/tex] must also be true.
- The implication [tex]$q \Rightarrow r$[/tex] means that if [tex]$q$[/tex] is true, then [tex]$r$[/tex] must also be true.

2. Combining Implications:
- Since [tex]$p \Rightarrow q$[/tex] implies [tex]$p$[/tex] leads to [tex]$q$[/tex], and [tex]$q \Rightarrow r$[/tex] implies [tex]$q$[/tex] leads to [tex]$r$[/tex], we can combine these implications.
- If [tex]$p$[/tex] is true, then [tex]$q$[/tex] must be true (from [tex]$p \Rightarrow q$[/tex]).
- Given [tex]$q$[/tex] is true, then [tex]$r$[/tex] must also be true (from [tex]$q \Rightarrow r$[/tex]).

3. Transitive Property:
- By the transitive property of implications, if [tex]$p$[/tex] leads to [tex]$q$[/tex] and [tex]$q$[/tex] leads to [tex]$r$[/tex], then [tex]$p$[/tex] must lead to [tex]$r$[/tex].
- Therefore, the combined implication is [tex]$p \Rightarrow r$[/tex].

Hence, the statement that must be true given [tex]$p \Rightarrow q$[/tex] and [tex]$q \Rightarrow r$[/tex] is:
[tex]\[ \boxed{p \Rightarrow r} \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{D} \][/tex]