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The surface area of a cone is [tex]\(216 \pi\)[/tex] square units. The height of the cone is [tex]\(\frac{5}{3}\)[/tex] times the radius.

What is the length of the radius of the cone to the nearest foot?

The radius is about [tex]\(10.5\)[/tex] feet.

Sagot :

Let's solve the problem step by step.

Given:
- The surface area of the cone is [tex]\(216 \pi\)[/tex] square units.
- The height of the cone, [tex]\(h\)[/tex], is [tex]\(\frac{5}{3}\)[/tex] times the radius, [tex]\(r\)[/tex].

The formula for the surface area of a cone is:

[tex]\[ \text{Surface area} = \pi r (r + l) \][/tex]

where [tex]\(l\)[/tex] is the slant height of the cone. The slant height [tex]\(l\)[/tex] can be calculated using the Pythagorean theorem:

[tex]\[ l = \sqrt{r^2 + h^2} \][/tex]

Since [tex]\(h = \frac{5}{3}r\)[/tex], substituting in we get:

[tex]\[ l = \sqrt{r^2 + \left(\frac{5}{3}r\right)^2} = \sqrt{r^2 + \frac{25}{9}r^2} = \sqrt{\left(1 + \frac{25}{9}\right)r^2} = \sqrt{\frac{34}{9}r^2} = \frac{\sqrt{34}}{3}r \][/tex]

Now, substituting [tex]\(l\)[/tex] back into the surface area equation:

[tex]\[ \pi r \left(r + \frac{\sqrt{34}}{3}r\right) = 216 \pi \][/tex]

Removing [tex]\(\pi\)[/tex] from both sides:

[tex]\[ r \left(r + \frac{\sqrt{34}}{3}r\right) = 216 \][/tex]

Simplifying further:

[tex]\[ r \left(r + \frac{\sqrt{34}}{3}r\right) = 216 \][/tex]
[tex]\[ r \left(1 + \frac{\sqrt{34}}{3}\right)r = 216 \][/tex]
[tex]\[ r^2 \left(1 + \frac{\sqrt{34}}{3}\right) = 216 \][/tex]

Let [tex]\(A = 1 + \frac{\sqrt{34}}{3}\)[/tex]:

[tex]\[ r^2 A = 216 \][/tex]

Solving for [tex]\(r^2\)[/tex]:

[tex]\[ r^2 = \frac{216}{A} \][/tex]

Now substituting the numerical values:

[tex]\[ A = 2.9436506316151005 \][/tex]
[tex]\[ r^2 = \frac{216}{2.9436506316151005} = 73.37827311439018 \][/tex]

Thus, the radius [tex]\(r\)[/tex] is:

[tex]\[ r = \sqrt{73.37827311439018} \approx 8.566111901813459 \, \text{feet} \][/tex]

Therefore, the radius of the cone is approximately [tex]\(9\)[/tex] feet to the nearest foot.