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Which equation represents a line that passes through (5,1) and has a slope of [tex]\(\frac{1}{2}\)[/tex]?

A. [tex]\(y - 5 = \frac{1}{2}(x - 1)\)[/tex]
B. [tex]\(y - \frac{1}{2} = 5(x - 1)\)[/tex]
C. [tex]\(y - 1 = \frac{1}{2}(x - 5)\)[/tex]
D. [tex]\(y - 1 = 5\left(x - \frac{1}{2}\right)\)[/tex]

Sagot :

Of course, let's go through the problem step by step to find which equation represents a line that passes through the point [tex]\((5, 1)\)[/tex] and has a slope of [tex]\(\frac{1}{2}\)[/tex].

1. Identify Point-Slope Form:
The point-slope form of a linear equation of a line with slope [tex]\(m\)[/tex] that passes through the point [tex]\((x_1, y_1)\)[/tex] is given by:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]

2. Substitute Given Values:
Here, the given slope [tex]\(m\)[/tex] is [tex]\(\frac{1}{2}\)[/tex], and the point [tex]\((x_1, y_1)\)[/tex] is [tex]\((5, 1)\)[/tex]. Substituting these into the point-slope form equation:
[tex]\[ y - 1 = \frac{1}{2}(x - 5) \][/tex]

3. Compare with Given Choices:
Now we compare our derived equation [tex]\(y - 1 = \frac{1}{2}(x - 5)\)[/tex] with the given choices:
[tex]\[ \begin{array}{l} y-5=\frac{1}{2}(x-1) \\ y-\frac{1}{2}=5(x-1) \\ y-1=\frac{1}{2}(x-5) \\ y-1=5\left(x-\frac{1}{2}\right) \end{array} \][/tex]

Clearly, the equation [tex]\(y - 1 = \frac{1}{2}(x - 5)\)[/tex] matches exactly with the given choice [tex]\(y-1=\frac{1}{2}(x-5)\)[/tex].

Therefore, the correct equation is:
[tex]\[ \boxed{y - 1 = \frac{1}{2}(x - 5)} \][/tex]

Among the choices, this corresponds to the third option. Thus, the correct answer is indeed:
[tex]\[ \boxed{3} \][/tex]