Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To determine the original dimensions of the photo before it was enlarged, we need to understand the relation between the original and the enlarged photo under the dilation process.
Given:
- The enlarged dimensions of the poster are [tex]\( 24 \times 32 \)[/tex] inches.
- The dilation factor is 4 ([tex]\( D_{Q, 4} \)[/tex]).
Here’s how we find the original dimensions:
1. Identify the enlarged dimensions:
The enlarged photo has dimensions 24 inches in width and 32 inches in height.
2. Understand the dilation factor:
A dilation factor of 4 means each dimension of the original photo is multiplied by 4 to get the enlarged dimensions.
3. Calculate the original dimensions:
- To find the original width, we divide the enlarged width by the dilation factor:
[tex]\[ \text{Original Width} = \frac{24 \text{ inches}}{4} = 6 \text{ inches} \][/tex]
- To find the original height, we divide the enlarged height by the dilation factor:
[tex]\[ \text{Original Height} = \frac{32 \text{ inches}}{4} = 8 \text{ inches} \][/tex]
Therefore, the dimensions of the original photo, before it was enlarged, are [tex]\( 6 \times 8 \)[/tex] inches.
So, the correct answer is:
[tex]\[ 6 \times 8 \][/tex]
Given:
- The enlarged dimensions of the poster are [tex]\( 24 \times 32 \)[/tex] inches.
- The dilation factor is 4 ([tex]\( D_{Q, 4} \)[/tex]).
Here’s how we find the original dimensions:
1. Identify the enlarged dimensions:
The enlarged photo has dimensions 24 inches in width and 32 inches in height.
2. Understand the dilation factor:
A dilation factor of 4 means each dimension of the original photo is multiplied by 4 to get the enlarged dimensions.
3. Calculate the original dimensions:
- To find the original width, we divide the enlarged width by the dilation factor:
[tex]\[ \text{Original Width} = \frac{24 \text{ inches}}{4} = 6 \text{ inches} \][/tex]
- To find the original height, we divide the enlarged height by the dilation factor:
[tex]\[ \text{Original Height} = \frac{32 \text{ inches}}{4} = 8 \text{ inches} \][/tex]
Therefore, the dimensions of the original photo, before it was enlarged, are [tex]\( 6 \times 8 \)[/tex] inches.
So, the correct answer is:
[tex]\[ 6 \times 8 \][/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.