Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Let's analyze the situation described:
1. Polly's Pushing Force:
- Polly is pushing a box to the right with a force of [tex]\(30 \, \text{N}\)[/tex].
2. Forces Acting on the Box:
- The force of gravity acting downwards is [tex]\(8 \, \text{N}\)[/tex].
- The normal force acting upwards is [tex]\(8 \, \text{N}\)[/tex].
3. Box is Not Moving:
- Given that Polly cannot move the box, it means the box is in static equilibrium. This implies that all the forces acting horizontally must balance each other out.
To achieve this balance:
- The force Polly exerts to push the box to the right is [tex]\(30 \, \text{N}\)[/tex].
- For the box to remain stationary (not moving), the force of friction, which opposes the motion, must be equal and opposite to Polly's pushing force.
Therefore, the force of friction must be exactly [tex]\( 30 \, \text{N} \)[/tex] acting to the left to balance Polly's pushing force.
Given the options:
- [tex]\( \leftarrow 30 \, \text{N} \)[/tex]
- [tex]\( \leftarrow 8 \, \text{N} \)[/tex]
- [tex]\( \rightarrow 8 \, \text{N} \)[/tex]
- [tex]\( \rightarrow 30 \, \text{N} \)[/tex]
The correct value that describes the force of friction is:
[tex]\[ \leftarrow 30 \, \text{N} \][/tex]
This indicates the force of friction is [tex]\(30 \, \text{N}\)[/tex] directed to the left.
1. Polly's Pushing Force:
- Polly is pushing a box to the right with a force of [tex]\(30 \, \text{N}\)[/tex].
2. Forces Acting on the Box:
- The force of gravity acting downwards is [tex]\(8 \, \text{N}\)[/tex].
- The normal force acting upwards is [tex]\(8 \, \text{N}\)[/tex].
3. Box is Not Moving:
- Given that Polly cannot move the box, it means the box is in static equilibrium. This implies that all the forces acting horizontally must balance each other out.
To achieve this balance:
- The force Polly exerts to push the box to the right is [tex]\(30 \, \text{N}\)[/tex].
- For the box to remain stationary (not moving), the force of friction, which opposes the motion, must be equal and opposite to Polly's pushing force.
Therefore, the force of friction must be exactly [tex]\( 30 \, \text{N} \)[/tex] acting to the left to balance Polly's pushing force.
Given the options:
- [tex]\( \leftarrow 30 \, \text{N} \)[/tex]
- [tex]\( \leftarrow 8 \, \text{N} \)[/tex]
- [tex]\( \rightarrow 8 \, \text{N} \)[/tex]
- [tex]\( \rightarrow 30 \, \text{N} \)[/tex]
The correct value that describes the force of friction is:
[tex]\[ \leftarrow 30 \, \text{N} \][/tex]
This indicates the force of friction is [tex]\(30 \, \text{N}\)[/tex] directed to the left.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.