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Sagot :
Sure, let's tackle this problem step by step:
1. Identify the original freezing point:
The freezing point of water is given as [tex]\( 32^{\circ} F \)[/tex].
2. Understand the effect of adding potassium:
Tim added potassium, which resulted in the freezing point of the water decreasing by [tex]\( 8^{\circ} F \)[/tex].
3. Deduct the temperature change from the original freezing point:
To find the new freezing point, we need to subtract the decrease from the original freezing point.
[tex]\[ \text{New freezing point} = \text{Original freezing point} - \text{Decrease in freezing point} \][/tex]
4. Substitute the values:
Let’s sub in the values we know:
[tex]\[ \text{Original freezing point} = 32^{\circ} F \][/tex]
[tex]\[ \text{Decrease in freezing point} = 8^{\circ} F \][/tex]
[tex]\[ \text{New freezing point} = 32^{\circ} F - 8^{\circ} F = 24^{\circ} F \][/tex]
So, after adding potassium, the new freezing point of the water is [tex]\( 24^{\circ} F \)[/tex].
1. Identify the original freezing point:
The freezing point of water is given as [tex]\( 32^{\circ} F \)[/tex].
2. Understand the effect of adding potassium:
Tim added potassium, which resulted in the freezing point of the water decreasing by [tex]\( 8^{\circ} F \)[/tex].
3. Deduct the temperature change from the original freezing point:
To find the new freezing point, we need to subtract the decrease from the original freezing point.
[tex]\[ \text{New freezing point} = \text{Original freezing point} - \text{Decrease in freezing point} \][/tex]
4. Substitute the values:
Let’s sub in the values we know:
[tex]\[ \text{Original freezing point} = 32^{\circ} F \][/tex]
[tex]\[ \text{Decrease in freezing point} = 8^{\circ} F \][/tex]
[tex]\[ \text{New freezing point} = 32^{\circ} F - 8^{\circ} F = 24^{\circ} F \][/tex]
So, after adding potassium, the new freezing point of the water is [tex]\( 24^{\circ} F \)[/tex].
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