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Use the following table to answer the question:

[tex]\[
\begin{array}{|l|l|l|l|}
\hline
\text{Strong acids} & \text{Weak acids} & \text{Weak bases} & \text{Strong bases} \\
\hline
\text{HBr} & \text{CH}_3\text{COOH} & \text{NH}_3 & \text{NaOH} \\
\hline
\text{HNO}_3 & \text{HF} & \text{NH}_4\text{OH} & \text{KOH} \\
\hline
\text{H}_2\text{SO}_4 & \text{HCN} & & \text{Ca(OH)}_2 \\
\hline
\end{array}
\][/tex]

Which reaction would yield a neutral salt?

A. [tex]\(2 \text{NaOH} + \text{H}_2\text{SO}_4\)[/tex]

B. [tex]\(\text{NaOH} + \text{HCN}\)[/tex]

C. [tex]\(\text{KOH} + \text{HF}\)[/tex]

D. [tex]\(2 \text{NH}_4\text{OH} + \text{H}_2\text{SO}_4\)[/tex]


Sagot :

To determine which reaction would yield a neutral salt, we need to analyze the nature of the acids and bases involved in each reaction given in the table.

1. [tex]$2 NaOH + H_2SO_4$[/tex]
- [tex]\(NaOH\)[/tex] is listed under strong bases.
- [tex]\(H_2SO_4\)[/tex] is listed under strong acids.
- A strong acid reacting with a strong base typically results in a neutral salt.
- Reaction: [tex]\(2 NaOH (strong\, base) + H_2SO_4 (strong\, acid)\)[/tex]
Yields a neutral salt ([tex]\(Na_2SO_4\)[/tex]) and water.

2. [tex]$NaOH + HCN$[/tex]
- [tex]\(NaOH\)[/tex] is listed under strong bases.
- [tex]\(HCN\)[/tex] is listed under weak acids.
- A strong base reacting with a weak acid results in a basic salt.
- Therefore, this reaction does not produce a neutral salt.

3. [tex]$KOH + HF$[/tex]
- [tex]\(KOH\)[/tex] is listed under strong bases.
- [tex]\(HF\)[/tex] is listed under weak acids.
- A strong base reacting with a weak acid results in a basic salt.
- Therefore, this reaction does not produce a neutral salt.

4. [tex]$2 NH_4OH + H_2SO_4$[/tex]
- [tex]\(NH_4OH\)[/tex] is listed under weak bases.
- [tex]\(H_2SO_4\)[/tex] is listed under strong acids.
- A weak base reacting with a strong acid results in an acidic salt.
- Therefore, this reaction does not produce a neutral salt.

From the above analysis, we can conclude that the reaction:

[tex]$2 NaOH + H_2SO_4$[/tex]

is the one that yields a neutral salt.
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