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What element has an electron configuration of [tex]\([Ar] \ 4s^2 \ 3d^{10}\)[/tex]?

A. Zn
B. Cd
C. Cu
D. Ga

Sagot :

To determine which element corresponds to the electron configuration [tex]\([Ar] 4s^2 3d^{10}\)[/tex], we need to analyze the given configuration in detail.

1. Identify the noble gas core:
- The configuration starts with [tex]\([Ar]\)[/tex], which represents the electron configuration of Argon. Argon (Ar) has 18 electrons.

2. Add the electrons in the outer shells:
- Following [tex]\([Ar]\)[/tex], we have [tex]\(4s^2\)[/tex], indicating 2 electrons in the 4s orbital.
- Next, we have [tex]\(3d^{10}\)[/tex], indicating 10 electrons in the 3d orbital.

3. Sum up the electrons:
- The number of electrons in Argon's configuration: 18
- Add 2 electrons from the [tex]\(4s^2\)[/tex] orbital: [tex]\(18 + 2 = 20\)[/tex]
- Add 10 electrons from the [tex]\(3d^{10}\)[/tex] orbital: [tex]\(20 + 10 = 30\)[/tex]

4. Identify the element:
- An element with 30 electrons corresponds to Zinc (Zn) on the periodic table.

Therefore, the element with the electron configuration [tex]\([Ar] 4s^2 3d^{10}\)[/tex] is Zinc (Zn).

So, the correct answer is:

[tex]\( \boxed{Zn} \)[/tex]