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Sagot :
To solve this problem, we need to determine the change in energy of the system, denoted as [tex]\(\Delta H\)[/tex].
We are given the following information:
- The energy absorbed by the reaction, [tex]\(Q\)[/tex], is [tex]\(150\)[/tex] joules (J).
- The work done on the syringe, [tex]\(W\)[/tex], is [tex]\(25\)[/tex] joules (J).
The formula to calculate the change in energy ([tex]\(\Delta H\)[/tex]) is given by:
[tex]\[ Q + W = \Delta H \][/tex]
Let's fill in the given values:
[tex]\[ 150\ J + 25\ J = \Delta H \][/tex]
Now, let's add these values together to find [tex]\(\Delta H\)[/tex]:
[tex]\[ 150\ J + 25\ J = 175\ J \][/tex]
So, the change in energy of the system, [tex]\(\Delta H\)[/tex], is [tex]\(175\)[/tex] joules.
Thus, the completed equation with the missing numbers is:
[tex]\[ 150\ J + 25\ J = 175\ J \][/tex]
We are given the following information:
- The energy absorbed by the reaction, [tex]\(Q\)[/tex], is [tex]\(150\)[/tex] joules (J).
- The work done on the syringe, [tex]\(W\)[/tex], is [tex]\(25\)[/tex] joules (J).
The formula to calculate the change in energy ([tex]\(\Delta H\)[/tex]) is given by:
[tex]\[ Q + W = \Delta H \][/tex]
Let's fill in the given values:
[tex]\[ 150\ J + 25\ J = \Delta H \][/tex]
Now, let's add these values together to find [tex]\(\Delta H\)[/tex]:
[tex]\[ 150\ J + 25\ J = 175\ J \][/tex]
So, the change in energy of the system, [tex]\(\Delta H\)[/tex], is [tex]\(175\)[/tex] joules.
Thus, the completed equation with the missing numbers is:
[tex]\[ 150\ J + 25\ J = 175\ J \][/tex]
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