Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

What is the axis of symmetry of [tex]\( h(x) = 5x^2 + 40x + 64 \)[/tex]?

A. [tex]\( x = -16 \)[/tex]
B. [tex]\( x = -4 \)[/tex]
C. [tex]\( x = 4 \)[/tex]
D. [tex]\( x = 16 \)[/tex]

Sagot :

GinnyAnswer
To determine the axis of symmetry for the quadratic function [tex]\( h(x) = 5x^2 + 40x + 64 \)[/tex], we use the formula for the axis of symmetry of a quadratic equation of the form [tex]\( ax^2 + bx + c \)[/tex]. The formula is:

[tex]\[ x = \frac{-b}{2a} \][/tex]

In this quadratic function, the coefficients are:
- [tex]\( a = 5 \)[/tex]
- [tex]\( b = 40 \)[/tex]

Plugging these values into the formula, we get:

[tex]\[ x = \frac{-40}{2 \cdot 5} \][/tex]
[tex]\[ x = \frac{-40}{10} \][/tex]
[tex]\[ x = -4 \][/tex]

Therefore, the axis of symmetry for the quadratic function [tex]\( h(x) = 5x^2 + 40x + 64 \)[/tex] is:

[tex]\[ x = -4 \][/tex]

So, the correct answer is:

[tex]\[ x = -4 \][/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.