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A triangle has vertices at [tex]\( B(-3,0), C(2,-1), D(-1,2) \)[/tex]. Which transformation would produce an image with vertices [tex]\( B''(-2,1), C''(3,2), D''(0,-1) \)[/tex]?

A. [tex]\((x, y) \rightarrow (x, -y) \rightarrow (x+1, y+1)\)[/tex]

B. [tex]\((x, y) \rightarrow (-x, y) \rightarrow (x+1, y+1)\)[/tex]

C. [tex]\((x, y) \rightarrow (x, -y) \rightarrow (x+2, y+2)\)[/tex]

D. [tex]\((x, y) \rightarrow (-x, y) \rightarrow (x+2, y+2)\)[/tex]

Sagot :

To solve this problem, we need to apply transformations to the initial vertices [tex]\( B(-3, 0), C(2, -1), D(-1, 2) \)[/tex] and see which sequence leads us to [tex]\( B^{\prime \prime}(-2,1), C^{\prime \prime}(3,2), D^{\prime \prime}(0,-1) \)[/tex].

Let's check the options provided step by step.

### Option 1: [tex]\((x, y) \rightarrow (x, -y) \rightarrow (x+1, y+1)\)[/tex]

First Transformation: [tex]\((x, y) \rightarrow (x, -y)\)[/tex]

- [tex]\( B(-3, 0) \rightarrow B'(-3, 0) \)[/tex]
- [tex]\( C(2, -1) \rightarrow C'(2, 1) \)[/tex]
- [tex]\( D(-1, 2) \rightarrow D'(-1, -2) \)[/tex]

Second Transformation: [tex]\((x, y) \rightarrow (x+1, y+1)\)[/tex]

- [tex]\( B'(-3, 0) \rightarrow B^{\prime \prime}(-2, 1) \)[/tex]
- [tex]\( C'(2, 1) \rightarrow C^{\prime \prime}(3, 2) \)[/tex]
- [tex]\( D'(-1, -2) \rightarrow D^{\prime \prime}(0, -1) \)[/tex]

As a result, we obtain the vertices:
- [tex]\( B^{\prime \prime}(-2, 1) \)[/tex]
- [tex]\( C^{\prime \prime}(3, 2) \)[/tex]
- [tex]\( D^{\prime \prime}(0, -1) \)[/tex]

This matches the target vertices. Therefore, Option 1 is the correct transformation sequence.

Given the correct transformation, we do not need to check the rest. But for completeness:

### Option 2: [tex]\((x, y) \rightarrow (-x, y) \rightarrow (x+1, y+1)\)[/tex]

First Transformation: [tex]\((x, y) \rightarrow (-x, y)\)[/tex]

- [tex]\( B(-3, 0) \rightarrow B'(3, 0) \)[/tex]
- [tex]\( C(2, -1) \rightarrow C'(-2, -1) \)[/tex]
- [tex]\( D(-1, 2) \rightarrow D'(1, 2) \)[/tex]

Second Transformation: [tex]\((x, y) \rightarrow (x+1, y+1)\)[/tex]

- [tex]\( B'(3, 0) \rightarrow B^{\prime \prime}(4, 1) \)[/tex]
- [tex]\( C'(-2, -1) \rightarrow C^{\prime \prime}(-1, 0) \)[/tex]
- [tex]\( D'(1, 2) \rightarrow D^{\prime \prime}(2, 3) \)[/tex]

These vertices do not match the target vertices.

### Option 3: [tex]\((x, y) \rightarrow (x, -y) \rightarrow (x+2, y+2)\)[/tex]

First Transformation: [tex]\((x, y) \rightarrow (x, -y)\)[/tex]

- [tex]\( B(-3, 0) \rightarrow B'(-3, 0) \)[/tex]
- [tex]\( C(2, -1) \rightarrow C'(2, 1) \)[/tex]
- [tex]\( D(-1, 2) \rightarrow D'(-1, -2) \)[/tex]

Second Transformation: [tex]\((x, y) \rightarrow (x+2, y+2)\)[/tex]

- [tex]\( B'(-3, 0) \rightarrow B^{\prime \prime}(-1, 2) \)[/tex]
- [tex]\( C'(2, 1) \rightarrow C^{\prime \prime}(4, 3) \)[/tex]
- [tex]\( D'(-1, -2) \rightarrow D^{\prime \prime}(1, 0) \)[/tex]

These vertices do not match the target vertices.

### Option 4: [tex]\((x, y) \rightarrow (-x, y) \rightarrow (x+2, y+2)\)[/tex]

First Transformation: [tex]\((x, y) \rightarrow (-x, y)\)[/tex]

- [tex]\( B(-3, 0) \rightarrow B'(3, 0) \)[/tex]
- [tex]\( C(2, -1) \rightarrow C'(-2, -1) \)[/tex]
- [tex]\( D(-1, 2) \rightarrow D'(1, 2) \)[/tex]

Second Transformation: [tex]\((x, y) \rightarrow (x+2, y+2)\)[/tex]

- [tex]\( B'(3, 0) \rightarrow B^{\prime \prime}(5, 2) \)[/tex]
- [tex]\( C'(-2, -1) \rightarrow C^{\prime \prime}(0, 1) \)[/tex]
- [tex]\( D'(1, 2) \rightarrow D^{\prime \prime}(3, 4) \)[/tex]

These vertices do not match the target vertices.

Therefore, the correct sequence of transformations to achieve the desired vertices is:
Option 1: [tex]\((x, y) \rightarrow (x, -y) \rightarrow (x+1, y+1)\)[/tex]