Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To solve the problem of finding [tex]\((f - g)(x)\)[/tex], where [tex]\(f(x) = 2 x^2 - 5\)[/tex] and [tex]\(g(x) = 3x + 3\)[/tex], we need to subtract the function [tex]\(g(x)\)[/tex] from the function [tex]\(f(x)\)[/tex]:
1. Write down the expressions for [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:
[tex]\[ f(x) = 2x^2 - 5 \][/tex]
[tex]\[ g(x) = 3x + 3 \][/tex]
2. Subtract [tex]\(g(x)\)[/tex] from [tex]\(f(x)\)[/tex]:
[tex]\[ (f - g)(x) = f(x) - g(x) = (2x^2 - 5) - (3x + 3) \][/tex]
3. Distribute the negative sign through the expression [tex]\(g(x)\)[/tex]:
[tex]\[ (f - g)(x) = 2x^2 - 5 - 3x - 3 \][/tex]
4. Combine like terms:
[tex]\[ (f - g)(x) = 2x^2 - 3x - 8 \][/tex]
So, the function [tex]\((f - g)(x)\)[/tex] is:
[tex]\[ (f - g)(x) = 2x^2 - 3x - 8 \][/tex]
Thus, the correct answer is:
B. [tex]\(2x^2 - 3x - 8\)[/tex]
1. Write down the expressions for [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:
[tex]\[ f(x) = 2x^2 - 5 \][/tex]
[tex]\[ g(x) = 3x + 3 \][/tex]
2. Subtract [tex]\(g(x)\)[/tex] from [tex]\(f(x)\)[/tex]:
[tex]\[ (f - g)(x) = f(x) - g(x) = (2x^2 - 5) - (3x + 3) \][/tex]
3. Distribute the negative sign through the expression [tex]\(g(x)\)[/tex]:
[tex]\[ (f - g)(x) = 2x^2 - 5 - 3x - 3 \][/tex]
4. Combine like terms:
[tex]\[ (f - g)(x) = 2x^2 - 3x - 8 \][/tex]
So, the function [tex]\((f - g)(x)\)[/tex] is:
[tex]\[ (f - g)(x) = 2x^2 - 3x - 8 \][/tex]
Thus, the correct answer is:
B. [tex]\(2x^2 - 3x - 8\)[/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.