Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To solve the problem, we need to understand the relationship between the force of gravity on an object and its mass.
Given:
- The force of gravity on an object ([tex]\(F\)[/tex]) varies directly with its mass ([tex]\(m\)[/tex]).
- The constant of variation due to gravity is 32.2 feet per second squared.
In direct variation, the relationship between two variables can be expressed using the equation:
[tex]\[ F = k \cdot m \][/tex]
where [tex]\(F\)[/tex] is the force, [tex]\(k\)[/tex] is the constant of variation (in this case, [tex]\(k = 32.2\)[/tex] ft/s[tex]\(^2\)[/tex]), and [tex]\(m\)[/tex] is the mass of the object.
Substituting the given constant of variation into the equation, we have:
[tex]\[ F = 32.2 \cdot m \][/tex]
This means the force [tex]\(F\)[/tex] can be calculated by multiplying the mass [tex]\(m\)[/tex] by the constant 32.2.
Now, we need to find the correct equation from the given options:
1. [tex]\(F = 16.1 m\)[/tex]
2. [tex]\(F = \frac{16.1}{m^2}\)[/tex]
3. [tex]\(F = 32.2 m\)[/tex]
4. [tex]\(F = \frac{32.2}{m^2}\)[/tex]
From our derived equation, [tex]\( F = 32.2 \cdot m \)[/tex], we observe that the correct corresponding option is:
[tex]\[ F = 32.2 m \][/tex]
Therefore, the correct choice is:
[tex]\[ \boxed{F = 32.2 m} \][/tex]
Given:
- The force of gravity on an object ([tex]\(F\)[/tex]) varies directly with its mass ([tex]\(m\)[/tex]).
- The constant of variation due to gravity is 32.2 feet per second squared.
In direct variation, the relationship between two variables can be expressed using the equation:
[tex]\[ F = k \cdot m \][/tex]
where [tex]\(F\)[/tex] is the force, [tex]\(k\)[/tex] is the constant of variation (in this case, [tex]\(k = 32.2\)[/tex] ft/s[tex]\(^2\)[/tex]), and [tex]\(m\)[/tex] is the mass of the object.
Substituting the given constant of variation into the equation, we have:
[tex]\[ F = 32.2 \cdot m \][/tex]
This means the force [tex]\(F\)[/tex] can be calculated by multiplying the mass [tex]\(m\)[/tex] by the constant 32.2.
Now, we need to find the correct equation from the given options:
1. [tex]\(F = 16.1 m\)[/tex]
2. [tex]\(F = \frac{16.1}{m^2}\)[/tex]
3. [tex]\(F = 32.2 m\)[/tex]
4. [tex]\(F = \frac{32.2}{m^2}\)[/tex]
From our derived equation, [tex]\( F = 32.2 \cdot m \)[/tex], we observe that the correct corresponding option is:
[tex]\[ F = 32.2 m \][/tex]
Therefore, the correct choice is:
[tex]\[ \boxed{F = 32.2 m} \][/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.