Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Sure, let's describe the key aspects of the function [tex]\( f(x) = -x^2 - 2x - 1 \)[/tex] step by step.
1. Vertex (Maximum Value):
- The function [tex]\( f(x) = -x^2 - 2x - 1 \)[/tex] is a quadratic equation in the form [tex]\( ax^2 + bx + c \)[/tex] with [tex]\( a = -1 \)[/tex], [tex]\( b = -2 \)[/tex], and [tex]\( c = -1 \)[/tex].
- For a quadratic function [tex]\( ax^2 + bx + c \)[/tex], the vertex is found using the formula [tex]\( x = -\frac{b}{2a} \)[/tex].
- Here, [tex]\( x = -\frac{-2}{2 \cdot (-1)} = 1 \)[/tex].
- To find the vertex's y-coordinate, substitute [tex]\( x = -1 \)[/tex] back into the function:
[tex]\[ f(-1) = -(-1)^2 - 2(-1) - 1 = -1 + 2 - 1 = 0 \][/tex]
- Thus, the vertex is at [tex]\((-1, 0)\)[/tex], and since the coefficient of [tex]\( x^2 \)[/tex] is negative, this vertex is the maximum value [tex]\( v \)[/tex].
2. Increasing Interval:
- A quadratic function [tex]\( f(x) = ax^2 + bx + c \)[/tex] with [tex]\( a < 0 \)[/tex] is upward-facing (concave down), meaning it decreases to the vertex and then increases after the vertex.
- Since our vertex is at [tex]\( x = -1 \)[/tex], the function is increasing on the interval [tex]\( (-1, \infty) \)[/tex].
3. Decreasing Interval:
- Similarly, the function is decreasing before the vertex. Therefore, it is decreasing on the interval [tex]\( (-\infty, -1] \)[/tex].
4. Domain:
- The domain of any quadratic function is all real numbers, which is [tex]\( (-\infty, \infty) \)[/tex].
5. Range:
- The range is determined by the vertex and the direction the parabola opens. Since the vertex is [tex]\((-1, 0)\)[/tex] and the parabola opens downwards, the range is from [tex]\( 0 \)[/tex] (the y-coordinate of the vertex) to negative infinity.
- Hence, the range of the function is [tex]\( (-\infty, 0] \)[/tex].
In summary:
- The vertex is the maximum value [tex]\( v \)[/tex].
- The function is increasing (choose the interval) [tex]\( (-1, \infty) \)[/tex].
- The function is decreasing (choose the interval) [tex]\( (-\infty, -1] \)[/tex].
- The domain of the function is [tex]\( (-\infty, \infty) \)[/tex].
- The range of the function is [tex]\( (-\infty, 0] \)[/tex].
1. Vertex (Maximum Value):
- The function [tex]\( f(x) = -x^2 - 2x - 1 \)[/tex] is a quadratic equation in the form [tex]\( ax^2 + bx + c \)[/tex] with [tex]\( a = -1 \)[/tex], [tex]\( b = -2 \)[/tex], and [tex]\( c = -1 \)[/tex].
- For a quadratic function [tex]\( ax^2 + bx + c \)[/tex], the vertex is found using the formula [tex]\( x = -\frac{b}{2a} \)[/tex].
- Here, [tex]\( x = -\frac{-2}{2 \cdot (-1)} = 1 \)[/tex].
- To find the vertex's y-coordinate, substitute [tex]\( x = -1 \)[/tex] back into the function:
[tex]\[ f(-1) = -(-1)^2 - 2(-1) - 1 = -1 + 2 - 1 = 0 \][/tex]
- Thus, the vertex is at [tex]\((-1, 0)\)[/tex], and since the coefficient of [tex]\( x^2 \)[/tex] is negative, this vertex is the maximum value [tex]\( v \)[/tex].
2. Increasing Interval:
- A quadratic function [tex]\( f(x) = ax^2 + bx + c \)[/tex] with [tex]\( a < 0 \)[/tex] is upward-facing (concave down), meaning it decreases to the vertex and then increases after the vertex.
- Since our vertex is at [tex]\( x = -1 \)[/tex], the function is increasing on the interval [tex]\( (-1, \infty) \)[/tex].
3. Decreasing Interval:
- Similarly, the function is decreasing before the vertex. Therefore, it is decreasing on the interval [tex]\( (-\infty, -1] \)[/tex].
4. Domain:
- The domain of any quadratic function is all real numbers, which is [tex]\( (-\infty, \infty) \)[/tex].
5. Range:
- The range is determined by the vertex and the direction the parabola opens. Since the vertex is [tex]\((-1, 0)\)[/tex] and the parabola opens downwards, the range is from [tex]\( 0 \)[/tex] (the y-coordinate of the vertex) to negative infinity.
- Hence, the range of the function is [tex]\( (-\infty, 0] \)[/tex].
In summary:
- The vertex is the maximum value [tex]\( v \)[/tex].
- The function is increasing (choose the interval) [tex]\( (-1, \infty) \)[/tex].
- The function is decreasing (choose the interval) [tex]\( (-\infty, -1] \)[/tex].
- The domain of the function is [tex]\( (-\infty, \infty) \)[/tex].
- The range of the function is [tex]\( (-\infty, 0] \)[/tex].
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.