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Sagot :
To find the relative frequency for the first class (80-89), follow these steps:
1. Identify the frequency of the first class: According to the table, the frequency for the score range 80-89 is 9.
2. Determine the total number of students: The total number of students is given as 50.
3. Calculate the relative frequency: The relative frequency is found by dividing the frequency of the first class by the total number of students.
[tex]\[ \text{Relative Frequency} = \frac{\text{Frequency of the first class}}{\text{Total number of students}} = \frac{9}{50} \][/tex]
4. Compute and round the relative frequency:
[tex]\[ \frac{9}{50} = 0.18 \][/tex]
Rounding to two decimal places, the result is 0.18.
5. Conclusion: Hence, the relative frequency for the first class (80-89) is 0.18.
[tex]\[ \text{Relative frequency} = 0.18 \][/tex]
1. Identify the frequency of the first class: According to the table, the frequency for the score range 80-89 is 9.
2. Determine the total number of students: The total number of students is given as 50.
3. Calculate the relative frequency: The relative frequency is found by dividing the frequency of the first class by the total number of students.
[tex]\[ \text{Relative Frequency} = \frac{\text{Frequency of the first class}}{\text{Total number of students}} = \frac{9}{50} \][/tex]
4. Compute and round the relative frequency:
[tex]\[ \frac{9}{50} = 0.18 \][/tex]
Rounding to two decimal places, the result is 0.18.
5. Conclusion: Hence, the relative frequency for the first class (80-89) is 0.18.
[tex]\[ \text{Relative frequency} = 0.18 \][/tex]
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