Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To determine which equation correctly represents a circle centered at the origin with a radius of 10, we need to recall the standard form of the equation for a circle. The standard form is:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
where [tex]\((h, k)\)[/tex] is the center of the circle and [tex]\(r\)[/tex] is the radius.
For a circle centered at the origin [tex]\((0,0)\)[/tex] with a radius of 10, we substitute [tex]\(h = 0\)[/tex], [tex]\(k = 0\)[/tex], and [tex]\(r = 10\)[/tex] into the standard form. This gives us the equation:
[tex]\[ (x - 0)^2 + (y - 0)^2 = 10^2 \][/tex]
Simplifying this, we have:
[tex]\[ x^2 + y^2 = 10^2 \][/tex]
And since [tex]\(10^2\)[/tex] equals 100, this further simplifies to:
[tex]\[ x^2 + y^2 = 100 \][/tex]
So the equation that represents a circle centered at the origin with a radius of 10 is:
[tex]\[ x^2 + y^2 = 100 \][/tex]
Among the given options, the correct one is:
B. [tex]\(x^2 + y^2 = 100\)[/tex]
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
where [tex]\((h, k)\)[/tex] is the center of the circle and [tex]\(r\)[/tex] is the radius.
For a circle centered at the origin [tex]\((0,0)\)[/tex] with a radius of 10, we substitute [tex]\(h = 0\)[/tex], [tex]\(k = 0\)[/tex], and [tex]\(r = 10\)[/tex] into the standard form. This gives us the equation:
[tex]\[ (x - 0)^2 + (y - 0)^2 = 10^2 \][/tex]
Simplifying this, we have:
[tex]\[ x^2 + y^2 = 10^2 \][/tex]
And since [tex]\(10^2\)[/tex] equals 100, this further simplifies to:
[tex]\[ x^2 + y^2 = 100 \][/tex]
So the equation that represents a circle centered at the origin with a radius of 10 is:
[tex]\[ x^2 + y^2 = 100 \][/tex]
Among the given options, the correct one is:
B. [tex]\(x^2 + y^2 = 100\)[/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.