Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To solve this problem, we follow these steps:
1. Identify Key Information:
- The vertex of the parabola (the lowest point) is given by [tex]$(h, k) = (90, 6)$[/tex]. This means the lowest point is at [tex]$x = 90$[/tex] feet, and its height above the roadway is [tex]$6$[/tex] feet.
- Another point on the parabola is given as [tex]$(x_1, y_1) = (30, 15)$[/tex]. This means when [tex]$x = 30$[/tex] feet, the height of the cable above the roadway is [tex]$15$[/tex] feet.
2. Form of the Parabolic Equation:
- The general quadratic equation for the parabola is [tex]\( y = a(x - h)^2 + k \)[/tex].
- Substituting the vertex [tex]$(h, k)$[/tex] into the equation, we get [tex]\( y = a(x - 90)^2 + 6 \)[/tex].
3. Determine the Constant [tex]\( a \)[/tex]:
- We know that when [tex]$x = 30$[/tex], [tex]$y = 15$[/tex], so we substitute these values into the equation to find [tex]\( a \)[/tex]:
[tex]\[ 15 = a(30 - 90)^2 + 6 \][/tex]
- Simplify the equation to find [tex]\( a \)[/tex]:
[tex]\[ 15 = a \cdot 3600 + 6 \][/tex]
[tex]\[ 15 - 6 = 3600a \][/tex]
[tex]\[ 9 = 3600a \][/tex]
[tex]\[ a = \frac{9}{3600} = 0.0025 \][/tex]
4. Parabolic Equation:
- With [tex]\( a = 0.0025 \)[/tex], the equation of the parabola becomes:
[tex]\[ y = 0.0025(x - 90)^2 + 6 \][/tex]
5. Height at the Left Bridge Support:
- To find the height at the left bridge support, we substitute [tex]$x = 0$[/tex] into the equation:
[tex]\[ y = 0.0025(0 - 90)^2 + 6 \][/tex]
- Simplify the expression to find the height:
[tex]\[ y = 0.0025 \cdot 8100 + 6 \][/tex]
[tex]\[ y = 20.25 + 6 \][/tex]
[tex]\[ y = 26.25 \][/tex]
Therefore, the height of the main cable where it attaches to the left bridge support is [tex]\( 26.25 \)[/tex] feet.
1. Identify Key Information:
- The vertex of the parabola (the lowest point) is given by [tex]$(h, k) = (90, 6)$[/tex]. This means the lowest point is at [tex]$x = 90$[/tex] feet, and its height above the roadway is [tex]$6$[/tex] feet.
- Another point on the parabola is given as [tex]$(x_1, y_1) = (30, 15)$[/tex]. This means when [tex]$x = 30$[/tex] feet, the height of the cable above the roadway is [tex]$15$[/tex] feet.
2. Form of the Parabolic Equation:
- The general quadratic equation for the parabola is [tex]\( y = a(x - h)^2 + k \)[/tex].
- Substituting the vertex [tex]$(h, k)$[/tex] into the equation, we get [tex]\( y = a(x - 90)^2 + 6 \)[/tex].
3. Determine the Constant [tex]\( a \)[/tex]:
- We know that when [tex]$x = 30$[/tex], [tex]$y = 15$[/tex], so we substitute these values into the equation to find [tex]\( a \)[/tex]:
[tex]\[ 15 = a(30 - 90)^2 + 6 \][/tex]
- Simplify the equation to find [tex]\( a \)[/tex]:
[tex]\[ 15 = a \cdot 3600 + 6 \][/tex]
[tex]\[ 15 - 6 = 3600a \][/tex]
[tex]\[ 9 = 3600a \][/tex]
[tex]\[ a = \frac{9}{3600} = 0.0025 \][/tex]
4. Parabolic Equation:
- With [tex]\( a = 0.0025 \)[/tex], the equation of the parabola becomes:
[tex]\[ y = 0.0025(x - 90)^2 + 6 \][/tex]
5. Height at the Left Bridge Support:
- To find the height at the left bridge support, we substitute [tex]$x = 0$[/tex] into the equation:
[tex]\[ y = 0.0025(0 - 90)^2 + 6 \][/tex]
- Simplify the expression to find the height:
[tex]\[ y = 0.0025 \cdot 8100 + 6 \][/tex]
[tex]\[ y = 20.25 + 6 \][/tex]
[tex]\[ y = 26.25 \][/tex]
Therefore, the height of the main cable where it attaches to the left bridge support is [tex]\( 26.25 \)[/tex] feet.
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.