Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

I NEED THIS BY TONIGHT
solve using compound inequality
3x-4>5 or 1-2x(greater than or equal to)7


Sagot :

Answer:

(-∞, 3] ∪ (3, ∞)

Step-by-step explanation:

Given compound inequality:

[tex]3x - 4 > 5\;\textsf{or}\;1 - 2x \geq 7[/tex]

To solve the compound equality, begin by solving each inequality separately.

Solve the first inequality:

[tex]3x-4 > 5 \\\\3x-4+4 > 5+4 \\\\3x > 9 \\\\x > \dfrac{9}{3} \\\\x > 3[/tex]

Solve the second inequality:

[tex]1-2x\geq 7 \\\\1-2x+2x\geq 7+2x \\\\1\geq 7+2x \\\\1-7\geq 7+2x-7 \\\\-6\geq 2x \\\\2x\leq -6 \\\\x\leq\dfrac{-6}{2}\\\\x\leq -3[/tex]

Therefore, the solutions to the individual inequalities are:

[tex]x > 3\\\\ x\leq-3[/tex]

Since these are "or" inequalities, we combine the solutions.

These are written with the symbol ∪ and represent the union of the solution sets, meaning the values that satisfy at least one of the inequalities.

Therefore, the solution to the compound inequality is:

[tex]\Large\boxed{\boxed{x\leq-3\;\textsf{or}\;x > 3}}[/tex]

In interval notation this is:

[tex]\Large\boxed{\boxed{(-\infty,-3]\cup(3,\infty)}}[/tex]