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To solve [tex]\( e^{4-3x} = \frac{4}{3}x + 9 \)[/tex] by graphing, which equations should be graphed?

A. [tex]\( y = 0 \)[/tex]
B. [tex]\( y = \frac{4}{3}x + 9 \)[/tex]
C. [tex]\( y = e^{4-3x} - \frac{4}{3}x + 9 \)[/tex]
D. [tex]\( y = \frac{4}{3}x + 9 + e^{4-3x} \)[/tex]
E. [tex]\( y = e^{4-3x} \)[/tex]

Sagot :

GinnyAnswer
To solve the equation [tex]\( e^{4-3x} = \frac{4}{3}x + 9 \)[/tex] by graphing, we need to graph two separate equations and find their intersection point.

The first equation is:
[tex]\[ y = e^{4-3x} \][/tex]

The second equation is:
[tex]\[ y = \frac{4}{3}x + 9 \][/tex]

By finding the point where these two graphs intersect, we can determine the solution to the original equation [tex]\( e^{4-3x} = \frac{4}{3}x + 9 \)[/tex].

Therefore, the equations to graph are:
[tex]\[ y = e^{4-3x} \][/tex]
and
[tex]\[ y = \frac{4}{3}x + 9 \][/tex]

Hence, the correct options to graph are:
- [tex]\( y = e^{4-3x} \)[/tex]
- [tex]\( y = \frac{4}{3}x + 9 \)[/tex]
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