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Choose an equation that would be used to solve

0 = -x² + 10x - 8

A. (x + 25)² = -8
B. (x - 5)² = 17
C. (x - 10)² = 25

Sagot :

To choose an equation that would be used to solve [tex]\(0 = -x^2 + 10x - 8\)[/tex], let us follow these steps:

1. Identify the type of equation:
The given equation [tex]\(0 = -x^2 + 10x - 8\)[/tex] is a quadratic equation. Quadratic equations often have solutions that can be expressed using the quadratic formula:

[tex]\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]

2. Rewrite the equation in standard form:
The standard form of a quadratic equation is [tex]\(ax^2 + bx + c = 0\)[/tex]. For the given equation:

[tex]\[ -x^2 + 10x - 8 = 0 \][/tex]

Here, the coefficients are:
[tex]\[ a = -1, \quad b = 10, \quad c = -8 \][/tex]

3. Calculate the discriminant:
The discriminant [tex]\(\Delta\)[/tex] of a quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex] is calculated as:

[tex]\[ \Delta = b^2 - 4ac \][/tex]

For the given coefficients:

[tex]\[ \Delta = 10^2 - 4 \cdot (-1) \cdot (-8) = 100 - 32 = 68 \][/tex]

4. Calculate the roots:
Using the quadratic formula:

[tex]\[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \][/tex]

Substituting in the values:

[tex]\[ x = \frac{-10 \pm \sqrt{68}}{-2} \][/tex]

Simplifying further, we get two roots (solutions):

[tex]\[ x_1 = \frac{-10 + \sqrt{68}}{-2}, \quad x_2 = \frac{-10 - \sqrt{68}}{-2} \][/tex]

Simplifying these, we get:

[tex]\[ x_1 = 5 - \sqrt{17}, \quad x_2 = 5 + \sqrt{17} \][/tex]

5. Formulating the factorized form:
The roots [tex]\(x_1\)[/tex] and [tex]\(x_2\)[/tex] can be used to generate the equation in the form [tex]\((x - x_1)(x - x_2) = 0\)[/tex]. Rewriting it:

[tex]\[ (x - (5 - \sqrt{17}))(x - (5 + \sqrt{17})) = 0 \][/tex]

6. Recognize the quadratic in vertex form:
With known roots, we can express the equation in vertex form, which looks like [tex]\((x - h)^2 = k\)[/tex].

The roots are symmetrically distributed around their average, which is the vertex:

[tex]\[ h = \frac{x_1 + x_2}{2} = \frac{(5 - \sqrt{17}) + (5 + \sqrt{17})}{2} = 5 \][/tex]

The constant term [tex]\(k\)[/tex] is derived from calculating:

[tex]\[ k = (x_1 - h)^2 = (x_2 - h)^2 = (\sqrt{17})^2 = 17 \][/tex]

Therefore, the correct equation that could be used to solve [tex]\(0 = -x^2 + 10x - 8\)[/tex] is:

[tex]\[ (x - 5)^2 = 17 \][/tex]